Spread Windows Forms 6.0 Product Documentation
GetDataRowFromModelRow Method
See Also  Example Support Options
FarPoint.Win.Spread Assembly > FarPoint.Win.Spread.Model Namespace > DefaultSheetDataModel Class : GetDataRowFromModelRow Method


row
Index of row in the model

Glossary Item Box

Gets the data source row index for the specified row in the model.

Syntax

Visual Basic (Declaration) 
Public Function GetDataRowFromModelRow( _
   ByVal row As Integer _
) As Integer
Visual Basic (Usage)Copy Code
Dim instance As DefaultSheetDataModel
Dim row As Integer
Dim value As Integer
 
value = instance.GetDataRowFromModelRow(row)
C# 
public int GetDataRowFromModelRow( 
   int row
)

Parameters

row
Index of row in the model

Return Value

Integer row index of the data source

Example

This example illustrates the use of this member by returning the data row from the specified index.
C#Copy Code
DataTable dt = new DataTable("Testing");
int i;
dt.Columns.Add("Number");
dt.Columns.Add("Letter");
dt.Rows.Add(new Object[]{"1", "One"});
dt.Rows.Add(new Object[] {"2", "Two"});
FarPoint.Win.Spread.Model.DefaultSheetDataModel dataModel = new FarPoint.Win.Spread.Model.DefaultSheetDataModel(dt);
fpSpread1.ActiveSheet.Models.Data = dataModel;
i = dataModel.GetDataRowFromModelRow(1);
listBox1.Items.Add(i.ToString());
Visual BasicCopy Code
Dim dt As New DataTable("Testing")
Dim i As Integer
dt.Columns.Add("Number")
dt.Columns.Add("Letter")
dt.Rows.Add(New Object() {"1", "One"})
dt.Rows.Add(New Object() {"2", "Two"})
Dim dataModel As New FarPoint.Win.Spread.Model.DefaultSheetDataModel(dt)
FpSpread1.ActiveSheet.Models.Data = dataModel
i = dataModel.GetDataRowFromModelRow(1)
ListBox1.Items.Add(i.ToString())

Requirements

Target Platforms: Windows 7, Windows Vista SP1 or later, Windows XP SP3, Windows Server 2008 (Server Core not supported), Windows Server 2008 R2 (Server Core supported with SP1 or later), Windows Server 2003 SP2

See Also

© 2002-2012 ComponentOne, a division of GrapeCity. All Rights Reserved.