Spread Windows Forms 7.0 Product Documentation
CanSerializeXml Property
See Also  Example Support Options
FarPoint.Win.Spread Assembly > FarPoint.Win.Spread.Model Namespace > DefaultSheetDataModel Class : CanSerializeXml Property


Glossary Item Box

Gets whether the object in its entirety can be rendered with XML without losing any information.

Syntax

Visual Basic (Declaration) 
Public ReadOnly Property CanSerializeXml As Boolean
Visual Basic (Usage)Copy Code
Dim instance As DefaultSheetDataModel
Dim value As Boolean
 
value = instance.CanSerializeXml
C# 
public bool CanSerializeXml {get;}

Property Value

Boolean: true if every contained object supports XML serialization; false otherwise

Remarks

This method returns true if the object can be rendered with XML in its entirety (using the Serialize method) without losing any information. This includes the data, any tags, or data source in the model associated with the object. Some objects can contain custom object references, such as a custom data type, that may or may not implement the XML serialization interface (ISerializeSupport). This method returns false if any of the contained objects do not implement the XML serialization interface.

Example

Visual BasicCopy Code
Dim dt As New DataTable("Testing")
dt.Columns.Add("Number")
dt.Columns.Add("Letter")
dt.Rows.Add(New Object() {"1", "One"})
dt.Rows.Add(New Object() {"2", "Two"})
Dim dataModel As New FarPoint.Win.Spread.Model.DefaultSheetDataModel(dt)
FpSpread1.ActiveSheet.Models.Data = dataModel
dataModel.SetModelDataColumn(0, "Letter")
dataModel.SetModelDataColumn(1, "Number")
Dim b As Boolean
b = dataModel.CanSerializeXml
ListBox1.Items.Add(b.ToString())
C#Copy Code
DataTable dt = new DataTable("Testing");
dt.Columns.Add("Number");
dt.Columns.Add("Letter");
dt.Rows.Add(new Object[]{"1", "One"});
dt.Rows.Add(new Object[] {"2", "Two"});
FarPoint.Win.Spread.Model.DefaultSheetDataModel dataModel = new FarPoint.Win.Spread.Model.DefaultSheetDataModel(dt);
fpSpread1.ActiveSheet.Models.Data = dataModel;
dataModel.SetModelDataColumn(0, "Letter");
dataModel.SetModelDataColumn(1, "Number");
bool b;
b = dataModel.CanSerializeXml;
listBox1.Items.Add(b.ToString());

Requirements

Target Platforms: Windows 2000 Professional (SP4), Windows 2000 Server, Windows 2003 Server (SP1), Windows 2008, Windows XP (SP2), Windows Vista, Windows 7, Windows 8

See Also

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