To extract a file from a zip to memory variable (for instance, a Byte array), use the following function:
Private Function GetDataFromZipFile(zipFileName As String, entryName As String) As Byte()
' Get the entry from the zip file.
Dim zip As New C1ZipFile()
zip.Open(zipFileName)
Dim ze As C1ZipEntry = zip.Entries(entryName)
' Copy the entry data into a memory stream.
Dim ms As New MemoryStream()
Dim buf(1000) As Byte
Dim s As Stream = ze.OpenReader()
Try
While True
Dim read As Integer = s.Read(buf, 0, buf.Length)
If read = 0 Then
Exit While
End If
ms.Write(buf, 0, read)
End While
Finally
s.Dispose()
End Try
s.Close()
' Return result.
Return ms.ToArray()
End Function
•C#
private byte[] GetDataFromZipFile(string zipFileName, string entryName)
{
// Get the entry from the zip file.
C1ZipFile zip = new C1ZipFile();
zip.Open(zipFileName);
C1ZipEntry ze = zip.Entries[entryName];
// Copy the entry data into a memory stream.
MemoryStream ms = new MemoryStream();
byte[] buf = new byte[1000];
using (Stream s = ze.OpenReader())
{
for (;;)
{
int read = s.Read(buf, 0, buf.Length);
if (read == 0) break;
ms.Write(buf, 0, read);
}
}
// There's no need to call close because of the C# 'using'
// statement above but in VB this would be necessary.
//s.Close();
// Return result.
return ms.ToArray();
}